Question

Write the electronic configuration of Ni2+ and mention the number of unpaired electrons

Answer 1

1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^6
Unpaired electrons- 4

Answer 2

Electronic configuration and unpaired electrons in $Ni^{2+}$

• To write electronic configuration of $Ni^{2+}$, first the electronic configuration of element Nickle must be written.
• To write it, the number of electrons present in Nickle must be known. We know that the atomic number represents the total number of electrons present in it.
• As the atomic number of Nickle is 28, it has 28 electrons.
• So the electronic configuration of nickle is $1s^22s^22p^63s^23p^63d^84s^2$. As $1s^22s^22p^63s^23p^6$ is electronic configuration of Nobel gas argon, it can be represented as $[Ar]3d^84s^2$.
• $Ni^{2+}$ means that the nickle has lost two electrons and thus its electronic configuration will be $[Ar]3d^8$.
• The number of unpaired electrons in $Ni^{2+}$ is 2.

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