Chemistry, asked by chandanreligare, 1 month ago

write the electronic configuration of Nitrogen Oxygen fluorine and neon their atomic number are 7, 8 ,9 and 10 respectively

Answers

Answered by aqtrgaming
2

Explanation:

Electronic configuration of

Nitrogen: 2,5

Oxygen: 2,6

Fluorine : 2,7

a) Fluorine (F) is most electronegative and nitrogen (N) is least electronegative.

b) Fluorine (F) has 7 valence electrons.

c) Valency of nitrogen is 3 and 5,valency of oxygen is 2, valency of fluorine is 1.

thanks you

Answered by MichTeddy
3

Answer:

Electronic configuration of

Electronic configuration of Nitrogen: 2,5

Electronic configuration of Nitrogen: 2,5Oxygen: 2,6

Electronic configuration of Nitrogen: 2,5Oxygen: 2,6 Fluorine : 2,7

Electronic configuration of Nitrogen: 2,5Oxygen: 2,6 Fluorine : 2,7a) Fluorine (F) is most electronegative and nitrogen (N) is least electronegative.

Electronic configuration of Nitrogen: 2,5Oxygen: 2,6 Fluorine : 2,7a) Fluorine (F) is most electronegative and nitrogen (N) is least electronegative.b) Fluorine (F) has 7 valence electrons.

Electronic configuration of Nitrogen: 2,5Oxygen: 2,6 Fluorine : 2,7a) Fluorine (F) is most electronegative and nitrogen (N) is least electronegative.b) Fluorine (F) has 7 valence electrons.c) Valency of nitrogen is 3 and 5,valency of oxygen is 2, valency of fluorine is 1.

Explanation:

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