write the electronic configuration of Nitrogen Oxygen fluorine and neon their atomic number are 7, 8 ,9 and 10 respectively
Answers
Explanation:
Electronic configuration of
Nitrogen: 2,5
Oxygen: 2,6
Fluorine : 2,7
a) Fluorine (F) is most electronegative and nitrogen (N) is least electronegative.
b) Fluorine (F) has 7 valence electrons.
c) Valency of nitrogen is 3 and 5,valency of oxygen is 2, valency of fluorine is 1.
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Answer:
Electronic configuration of
Electronic configuration of Nitrogen: 2,5
Electronic configuration of Nitrogen: 2,5Oxygen: 2,6
Electronic configuration of Nitrogen: 2,5Oxygen: 2,6 Fluorine : 2,7
Electronic configuration of Nitrogen: 2,5Oxygen: 2,6 Fluorine : 2,7a) Fluorine (F) is most electronegative and nitrogen (N) is least electronegative.
Electronic configuration of Nitrogen: 2,5Oxygen: 2,6 Fluorine : 2,7a) Fluorine (F) is most electronegative and nitrogen (N) is least electronegative.b) Fluorine (F) has 7 valence electrons.
Electronic configuration of Nitrogen: 2,5Oxygen: 2,6 Fluorine : 2,7a) Fluorine (F) is most electronegative and nitrogen (N) is least electronegative.b) Fluorine (F) has 7 valence electrons.c) Valency of nitrogen is 3 and 5,valency of oxygen is 2, valency of fluorine is 1.
Explanation:
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