Question

Write the electronic configuration of sodium atom (Na) and sodium ion (Na+
). Why there is difference in the electronic configuration of two

Answer 1

Answer:

Electronic configuration of Na: $1s^{2}2s^{2} 2p^{6} 3s^{1}$

Electronic configuration of $Na^{+}$: $1s^{2}2s^{2} 2p^{6}$

Explanation:

We know that the number of electrons present in the Na atom = 11

Therefore the electronic configuration of the sodium atom is $1s^{2}2s^{2} 2p^{6} 3s^{1}$

One electron is less in sodium ion($Na^{+}$)

That is the total number of electrons present in $Na^{+}$ = 11 - 1 = 10

Therefore the electronic configuration of the sodium ion is $1s^{2}2s^{2} 2p^{6}$