write the electronic configuration of the atoms of elements with atomic no 53 ,38,31,87.
Answers
Explanation:
This list of electron configurations of elements contains all the elements in increasing order of atomic number.
To save room, the configurations are in noble gas shorthand. This means part of the electron configuration has been replaced with the element symbol of the noble gas symbol. Look up the electronic configuration of that noble gas and include that value before the rest of the configuration.
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Answer:
Answer:
Given :-
Sides of triangular plot = 2:3:4
Perimeter = 450 m
To Find :-
Area
Solution :-
Let sides be x
Firstly let's find all sides of triangle
As we know that Perimeter is the sum of all sides
\sf \: 2x + 3x + 4x = 4502x+3x+4x=450
\sf \: 9x = 4509x=450
\sf \: x = \dfrac{450}{9}x=
9
450
\sf \: x = 50x=50
Let's find angles
\sf \: 2(50) = 1002(50)=100
\sf3(50) = 1503(50)=150
\sf \: 4(50) = 2004(50)=200
Now,
Let's find its semiperimeter
\sf \: s = \dfrac{a + b + c}{2}s=
2
a+b+c
\sf \: s = \dfrac{100 + 150 + 200}{2}s=
2
100+150+200
\sf \: s = \dfrac{450}{2} = 225s=
2
450
=225
Now,
Let's find Area by herons formula.
\huge \bf \green{\sqrt{s(s - a)(s - b)(s - c)} }
s(s−a)(s−b)(s−c)
\tt \mapsto \sqrt{225(225- 100)(225 - 150)(225 - 200)}↦
225(225−100)(225−150)(225−200)
\tt \mapsto \: \sqrt{225\times 125\times 75 \times 25}↦
225×125×75×25
\tt \mapsto \: \sqrt{(15 \times 15) (25 \times 5)(25 \times 3)(5 \times 5)}↦
(15×15)(25×5)(25×3)(5×5)
\tt\sqrt{15 {}^{2} \times 5{}^{2} \times 5 \times {5}^{2} \times }
15
2
×5
2
×5×5
2
×
\tt \: 1875× \sqrt{15}1875×
15
\huge \tt \mapsto 1875× \sqrt{15}{m}^{2}↦1875×
15
m
2
Diagram :-
\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1, 0)(1,0)(3,3)\qbezier(5,0)(5,0)(3,3)\qbezier(5,0)(1,0)(1,0)\put(2.85,3.2){$\bf A$}\put(0.5,-0.3){$\bf C$}\put(5.2,-0.3){$\bf B$}\end{picture}