Question

Write the electronic configuration of the elements platinum and gold

Answer 1

Answer:

#electronic configuration of platinum (Z=78) is [Xe] 4f14 5d9 6s1. It has one unpaired electron in its d-orbital and one unpaired electron in its s-orbita

#The electronic configuration of Gold is Xe 4f145d106s1.

Answer 2

Answer:

The electronic configuration of given elements are -

Platinum - [Xe] $\pmb{4f^{14} 5d^{9} 6s^{1}}$

Gold        - [Xe]  $\pmb{4f^{14} 5d^{10} 6s^{1}}$

Explanation:

• Electronic configuration in atomic physics and quantum chemistry can be explained as the distribution of electrons in atomic/molecular orbitals of an atom or molecule.
• It will describe that in an orbit each electron is moving independently, in an overall field created by other orbitals.
• For example, the electronic configuration of platinum and gold is  $\pmb{4f^{14} 5d^{9} 6s^{1}}$ and $\pmb{4f^{14} 5d^{10} 6s^{1}}$4f, 5d, 6s subshells will be occupied by 4, 5 and 6 electrons respectively.
• The platinum and gold are commonly used for jewelry making because of its characteristics like soft texture and are chemically low or unreactive.