Question

write the electronic configuration of the following and calculate the bond order. He2, He^+2 Li2, Be2 B2 C2 F2 and Ne2​

Answer 1

Answer:

Six species are diamagentic as all electrons are paired. These are

H

2

(σ1s)

2

,

Li

2

KK(σ2s)

2

,

Be

2

KK(σ2s)

2

(σ

∗

2s)

2

,

C

2

KK(σ2s)

2

(σ

∗

2s)

2

(π2p

y

)

2

(π2p

z

)

2

,

N

2

KK(σ2s)

2

(σ

∗

2s)

2

(π2p

y

)

2

(π2p

z

)

2

(σ2px)

2

F

2

KK(σ2s)

2

(σ

∗

2s)

2

(σ2px)

2

(π2p

y

)

2

(π2p

z

)

2

(π

∗

2p

y

)

2

(π

∗

2p

z

)

2

.

Three species are paramgnetic as unpaired electrons are present.These are

He

2

+

(σ1s)

2

(σ

∗

1s)

1

B

2

KK(σ2s)

2

(σ

∗

2s)

2

(π2p

y

)

1

(π2p

z

)

1

O

2

−

KK(σ2s)

2

(σ

∗

2s)

2

(σ2px)

2

(π2p

y

)

2

(π2p

z

)

2

(π

∗

2p

y

)

1

(π

∗

2p

z

)

1

.