Question

Write the electronic configuration of the following elements:
i) Sodium [Na=11]
ii) Oxygen [O = 16]
iii) Fluorine [F = 9]
iv) Potassium [ K = 19]​

Answer 1

Answer:

Sodium- [Ne] 3s1

Oxygen- [He] 2s2 2p4

Flurin- [He] 2s2 2p5

Pottasium- [Ar] 4s1

Explanation:

Some more info about electronic configuration-

In atomic physics and quantum chemistry, the electron configuration is the distribution of electrons of an atom or molecule (or other physical structure) in atomic or molecular orbitals.[1] For example, the electron configuration of the neon atom is 1s2 2s2 2p6, meaning that the 1s, 2s and 2p subshells are occupied by 2, 2 and 6 electrons respectively.

Electronic configurations describe each electron as moving independently in an orbital, in an average field created by all other orbitals. Mathematically, configurations are described by Slater determinants or configuration state functions.

According to the laws of quantum mechanics, for systems with only one electron, a level of energy is associated with each electron configuration and in certain conditions, electrons are able to move from one configuration to another by the emission or absorption of a quantum of energy, in the form of a photon.

Knowledge of the electron configuration of different atoms is useful in understanding the structure of the periodic table of elements. This is also useful for describing the chemical bonds that hold atoms together. In bulk materials, this same idea helps explain the peculiar properties of lasers and semiconductors.

Answer 2

This will be the answer