Question

Write the electronic configuration of two elements p and q having the atomic number are 17 and 19 determine there group number and periodic number

Answer 1

Answer:

17- 2,8,7 belongs17 group 3 period

19-2,8,8,1 belons to first group and 4 period

Answer 2

$Cl:17:1s^22s^22p^63s^23p^5$ group no : 17 period no : 3

$K:19:1s^22s^22p^63s^23p^64s^1$ group no : 1 period no : 4

Explanation:

Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom.

The electrons are filled according to Afbau's rule in order of increasing energies.

$Cl:17:1s^22s^22p^63s^23p^5$

In the given configuration, 3 is the highest principle quantum number. Therefore, it belongs to the 3rd period in the periodic table.

As the element belongs to p-block, as last electron enters p orbital,  its group number = (10+valence electrons) = 10+7= 17.

$K:19:1s^22s^22p^63s^23p^64s^1$

In the given configuration, 4 is the highest principle quantum number. Therefore, it belongs to the 4th period in the periodic table.

As the element belongs to s-block, as last electron enters s orbital,  its group number = valence electrons = 1

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