Chemistry, asked by clemencygillespie, 11 months ago

Write the electronic configuration using shorthand orbital method for Ga 3+ and Pb2+

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Answered by aabidhaanand
2

Answer:the electronic configuration using shorthand orbital method for Ga 3+ and Pb2+-

Explanation:The most common electron configuration for the gallium ion, Ga3+ is

1s22s22p63s23p63d10 or [Ar]3d10

Gallium is in Group 13. It has 31 electrons.

Its electron configuration is 1s22s22p63s23p63d104s24p

We form cations by removing electrons first from the outermost p orbitals, followed by the s orbital and finally the d orbitals (if any more electrons need to be removed).

The options for Ga would be to remove

   the 4p electron and form Ga+

   the 4p electron and both 4s electrons and form Ga3+.

By far the most common ion of Group 13 metals is +3.

So. the most common gallium ion is Ga3+, and its electron configuration is [Ar]3d10.

and for ,Pb2+ →→[Xe]4f145d106s2  

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