Question

write the electronic distribution of atom in 12 elements​

Answer 1

Answer:

a. Carbon

Atomic number = 6

Mass Number = 12

No. of protons = 6

No. of electrons = 6

No. of neutrons = 12 - 6 = 6

Electronic configuration - (K, L) = (2, 4)

b. Oxygen

Atomic number = 8

Mass Number = 16

No. of protons = 8

No. of electrons = 8

No. of neutrons = 16 - 8 = 8

Electronic configuration - (K, L) = (2, 6)

c. Phosphorus

Atomic number = 15

Mass Number = 31

No. of protons = 15

No. of electrons = 15

No. of neutrons = 31 - 15 = 16

Electronic configuration - (K, L, M) = (2, 8, 5)

d. Argon

Atomic number = 18

Mass Number = 40

No. of protons = 18

No. of electrons = 18

No. of neutrons = 40 - 18 = 12

Electronic configuration - (K, L, M) = (2, 8, 8)

e. Calcium

Atomic number = 20

Mass Number = 40

No. of protons = 20

No. of electrons = 20

No. of neutrons = 40 - 20 = 20

Electronic configuration - (K, L, M, N) = (2, 8, 8, 2)

Answer 2

$\huge \blue {Answer}$

2 , 8 , 8 , 2

valency is 2

element is calcium