Science, asked by Anonymous, 7 hours ago

Write the empirical formulae for :
Benzene, Acetic acid, Butane, Octane.

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Answers

Answered by CopyThat
14

Explanation:

Benzene :

Molecular formula = C₆H₆

We have,

  • C-atoms = 6
  • H-atoms = 6

Empirical formula :

  • 6/6
  • 1:1

CH is the empirical formula of Benzene.

Acetic acid :

Molecular formula = CH₃COOH

We have,

  • C-atoms = 2
  • H-atoms = 4
  • O-atoms = 2

Empirical formula :

  • 2/4/2
  • 1:2:1

CH₂O is the empirical formula of Acetic acid.

Butane :

Molecular formula = C₄H₁₀

We have,

  • C-atoms = 4
  • H-atoms = 10

Empirical formula :

  • 4/10
  • 2:5

C₂H₅ is the empirical formula of Butane.

Octane :

Molecular formula : C₈H₁₈

We have,

  • C-atoms = 8
  • H-atoms = 18

Empirical formula :

  • 8/18
  • 4:9

C₄H₉ is the empirical formula of Octane.

Learn more:

Molecular formula : It represents the actual number of atoms of each element in a molecule of a compound.

Empirical formula : It represents the simplest whole number ratio between the elements of a compound.

Answered by itzyourdeputygirl
8

(A) Benzene (C 6H 6 )-

(A) Benzene (C 6H 6 )-Ratio of atoms-

(A) Benzene (C 6H 6 )-Ratio of atoms- C:H=6:6=1:1

(A) Benzene (C 6H 6 )-Ratio of atoms- C:H=6:6=1:1∴ Empirical formula will be →CH

(A) Benzene (C 6H 6 )-Ratio of atoms- C:H=6:6=1:1∴ Empirical formula will be →CH(B) Glucose (C 6H12 O6 )-

(A) Benzene (C 6H 6 )-Ratio of atoms- C:H=6:6=1:1∴ Empirical formula will be →CH(B) Glucose (C 6H12 O6 )-Ratio of atoms-

(A) Benzene (C 6H 6 )-Ratio of atoms- C:H=6:6=1:1∴ Empirical formula will be →CH(B) Glucose (C 6H12 O6 )-Ratio of atoms-C:H:O=6:12:6=1:2:1

(A) Benzene (C 6H 6 )-Ratio of atoms- C:H=6:6=1:1∴ Empirical formula will be →CH(B) Glucose (C 6H12 O6 )-Ratio of atoms-C:H:O=6:12:6=1:2:1∴ Empirical formula will be →CH 2O

(C) Acetylene (C 2H 2)-

(C) Acetylene (C 2H 2)-Ratio of atoms-

(C) Acetylene (C 2H 2)-Ratio of atoms- C:H=2:2=1:1

(C) Acetylene (C 2H 2)-Ratio of atoms- C:H=2:2=1:1∴ Empirical formula will be →CH

(C) Acetylene (C 2H 2)-Ratio of atoms- C:H=2:2=1:1∴ Empirical formula will be →CH(A) Hydrogen per oxide

(H 2O 2)-

)-Ratio of atoms-

)-Ratio of atoms- H:O=2:2=1:1

)-Ratio of atoms- H:O=2:2=1:1∴ Empirical formula will be →HO

Hope it's help....

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