Question

Write the empirical formulae of the following:

(i)$N_2O_4$
(ii)$C_6H_6$
(iii)$C_6H_12O_6$
(iv)$H_2O$
(v)$H_2O_2$

$\purple\implies$ If possible, tell the method also.

$\sf\red{Note}$ - For Class 11 & above
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Answer 1

Answer:

Empirical formula → A formula giving the proportions of the elements present in a compound but not the actual numbers or arrangement of atoms.

In other words, empirical formula can be defined as the simplest form of molecular formula.

(A) Benzene (C6H6)-

Ratio of atoms- 

C:H=6:6=1:1

∴ Empirical formula will be →CH

(B) Glucose (C6H12O6)-

Ratio of atoms-

C:H:O=6:12:6=1:2:1

∴ Empirical formula will be →CH2O

(C) Acetylene (C2H2)-

Ratio of atoms- 

C:H=2:2=1:1

∴ Empirical formula will be →CH

(A) Hydrogen per oxide (H2O2)-

Ratio of atoms- 

H:O=2:2=1:1

∴ Empirical formula will be →HO

Answer 2

$\huge \bold \red {Answer:-}$

What is Empirical Formula?

→ It represents the simplest relative cohole of atoms of each element present in number ratio the molecule of the substance.

(i) N₂O₄➜ NO₂

Ratio of atoms → N:0 = 2:4 = 1:2

∴ Empirical formula will be → NO₂

where, n = 2

(ii) C₆H₆ ➜CH

Ratio of atoms C: H=6:6 = 1:1

∴ Empirical formula will be → CH

(iii) C₆H₁₂O₆ ➜ CH₂O

Ratio of atoms → C:H:0 = 6:12:6 = 1:2:1

∴ Empirical formula will be → CH₂O

(iv) H₂O ➜ H₂O

=> Since OH2 is the simplest whole number ratio it is indeed the empirical formula.

(v) H₂O₂➜ HO

Ratio of atoms → H:0 = 2:2=1:1

∴ Empirical formula will be → HO

Hope it helps :)