Question

Write the equation 4x = 6(1 - y) + 3x in the form ax + by = c and also find the co-ordinate of the
points where its graph cuts the two axes ?
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Answer 1

Answer:

4x = 6(1-y) +3x

4x = 6-6y+3x

x+6y=6

a=1

b=6

c=6

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put x=0

6y=6

y=1

point on y axis is (0,1)

put y=0

x=6

point on x axis is (6,0)

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Answer 2

Answer:

(6,0) (0,1)

Step-by-step explanation:

4x = 6(1-y) + 3x

4x = 6 - 6y + 3x

4x - 3x + 6y - 6 = 0

x + 6y - 6 = 0

1.x + 6.y + (-6) = 0 ---------(1)

which is in the form of ax + by + c = 0

Now, y=0 for any point on the x-axis

Putting y=0 in (1), we get:

x - 6 = 0

x = 6

so, co-ordinate of the point where the graph cuts the x-axis is (6,0)

Again, x=0 for any point on the y-axis

Putting x = 0 in (1), we get:

6y - 6 = 0

6y = 6

y = 6/6 = 1

so, co-ordinate of the point where the graph cuts the y-axis is (0,1)

I hope it helps:)