Question

Write the equation and solve it: perimeter of rectangle is 20m. It length is 2m greater than its breadth( take breadth as y)

Answer 1

Answer:

let breadth=y m

length=y+2 m

perimeter= 2 (L+B)

20 =2 (Y+2+Y)

20 =2 (2Y+2)

20 =4Y+4

20-4=4Y

16/4=Y

Y=4

length=4+2=6m

breath=4m

Answer 2

Answer:

Length and breadth of rectangle are 6 m and 4 m respectively

Step-by-step explanation:

Given that perimeter of rectangle is 20m

Also, length is 2m greater than its breadth

Let breadth of rectangle be $y$ m

Thus, length of rectange $=y + 2$ m

We know, Perimeter of rectangle is given as

$Perimeter = 2Length + 2Breadth\\\\ 20 = 2(\,y + 2)\, + 2y\\\\ 20 = 2y + 4 + 2y\\\\4y = 20 - 4\\\\ 4y = 16\\\\ y = 4$

Thus, we have

Breadth of rectangle $= 4$ m

Length of rectangle $= 4 + 2 = 6$ m