Write the equation for force on a current carrying wire in a magnetic field
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Your equation will be
F = ILB× angle in sin theta
Because in this case
F is directly proportional to current (1)
F is directly proportional to length of wire (2)
F is directly proportional to magnetic field applied (3)
On combining all three equations we get
F = ILB × angle of sine theta
F = ILB× angle in sin theta
Because in this case
F is directly proportional to current (1)
F is directly proportional to length of wire (2)
F is directly proportional to magnetic field applied (3)
On combining all three equations we get
F = ILB × angle of sine theta
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Answer:
F=BILSin0
F=qVBsin0
Explanation:
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