Write the equation for heating of Blue Hydrous Copper Sulphate Crystals( CuSO⁴.5H²O) and also for the addition of drops to the Anhydrous Copper Sulphate (white is colour).
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Answer:
Copper sulfate is normally found in the form of blue crystals, copper (II) sulfate pentahydrate and on heating copper sulfate pentahydrate turns white due to loss of water from blue copper sulfate.It has water of hydration which forms water vapour on heating, leaving white anhydrous copper sulphate.
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Answer:
copper sulphate pentahydrate that is blue vitriol has 5 water molecules so its water of crystallization is 5 when the blue colour of copper sulphate crystals are gently heated it loses its five molecules of water and becomes colourless anhydrous copper sulphate.
heating
CuSo4 . 5H2O ---------> CuSo4 + 5H2O
^ <--------- ^
| cooling |
(blue colour) (colourless)
if we add few drops of water or allow it to cool the colourless anhydrous salt again turns back into blue coloured hydrated salt.
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