write the equation for the laboratory preparation of:ethylene from1,2,dibromoethane
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Answer:
Reaction:
CH
2
Br−CH
2
Br
alc.KOH
CH
2
=CHBr
NaNH
2
CH≡CH (ethyne)
In the reaction first β elimination reaction of the alkyl halide takes place to form the corresponding alkene. This alkene on reaction with sodamide forms corresponding alkyne.(As NaNH
2
is strong base)
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