Question

write the equation in ax²+bx²+c=0 find the value of a, b, c x+¹/x=-5​

Answer 1

given by quadratic equation:-

\begin{gathered} {(x - 1)}^{2} = 2x + 3 \\ {x}^{2} + 1 - 2x = 2x + 3 \\ {x}^{2} + 1 - 2x - 2x - 3 = 0 \\ {x}^{2} - 4x - 2 = 0 \\ at \: the \: compare \: with \: genral \: formula \: of \: quadratic \: equation \: \\ a {x}^{2} + bx + c = 0 \\ we \: have \: \\ a = 1 \\ b = - 4 \\ c = - 2 \\ hence \: the \: value \: of \: a \: b \: c \: are \: 1 \: - 4 \: - 2.\end{gathered}

(x−1)

2

=2x+3

x

2

+1−2x=2x+3

x

2

+1−2x−2x−3=0

x

2

−4x−2=0

atthecomparewithgenralformulaofquadraticequation

ax

2

+bx+c=0

wehave

a=1

b=−4

c=−2

hencethevalueofabcare1−4−2.

(a , b , c ) = ( 1 , -4 , -2) ans