write the equation of a lim passing through point (2,3) amd makes an angle of 45° with x-axis
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Answered by
10
HEY MATE......
HERE'S THE ANSWER OF YOUR QUESTION
_________________________________
We have,
m= tan theta= tan45°=1
equation of straight line is,y-y1= m(x-x1)
> y-3=1(x-2)
> y-3=x-2
> y=x+1.....@ns
HERE'S THE ANSWER OF YOUR QUESTION
_________________________________
We have,
m= tan theta= tan45°=1
equation of straight line is,y-y1= m(x-x1)
> y-3=1(x-2)
> y-3=x-2
> y=x+1.....@ns
Varun151:
hi
Answered by
1
slope= m = tan45° = 1
y = mx + c
y = 1x + c
put (2,3) in it
3 = 2 + c
c = 1
therefore equation of line is
y = x + 1
y = mx + c
y = 1x + c
put (2,3) in it
3 = 2 + c
c = 1
therefore equation of line is
y = x + 1
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