Question

write the equation of a line that is perpendicular to 2x+3y = -12 and passes through the point (0,0)

Answer 1

Answer:

the equation of a line that is perpendicular to 2x+3y = -12 and passes through the point (0,0)

slope m = 3/2

Slope of perpendicular = - 3/2

So the required equation is,

2x-3y = -12

Answer 2

Answer:

y = 1.5x

Step-by-step explanation:

as the line passes through origin hence y-intercept is zero.

then calculate the gradient of the line whose equation is already given. the gradient of the line (2x +3y = -12 ) is -2/3.

to find gradient of perpendicular line, divide this gradient by -1.

input the gradient and you have your equation !!