Math, asked by 1072979, 1 month ago

Write the equation of a line that is perpendicular to the line y=13x+4 and passes through the point (2,−5).

The equation of the perpendicular line in slope-intercept form is:

Answers

Answered by narendrkumar42
0

Answer:

y = ( - 1 \div 13)x + ( - 63 \div 13)

Step-by-step explanation:

Given line

y = 13x + 4  \:  \:  \:  \\ so \: \:  \:  \: slope \:  of \: given \: line \:  =  13

Slope of perpendicular line is (-1÷13)

So equation of perpendicular line is

y = ( - 1 \div 13)x + c

Since line passes through point (2,-5). So

 - 5 = ( - 1 \div 13) \times 2 + c

So,

c = 63 \div 13

So equation of line in slope intercept form is

y = ( - 1 \div 13)x + ( - 63 \div 13)

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