Question

write the equation of a line that is perpendicular to the line y=2x+3 and that passes through the point (1,5)

Answer 1

Hello,

Solution:

Equation of line

$(x - x1) = m(y - y1)$
here m is slope of line.to find slope

$y = 2x + 3 \\ y = 2x \\ \\ m = \frac{y}{x} = 2$
Since line is perpendicular to this line,so slope is

m = -1/2

Equation of line is

$(x - x1) = m(y - y1) \\ \\ (x - 1) = \frac{ - 1}{2} (y - 5) \\ \\ 2x - 2 = - y + 5 \\ \\ 2x + y = 5 + 2 \\ \\ 2x + y = 7$
is the equation of line which passes through (1,5) and perpendicular to y= 2x+3

Hope it helps you