write the equation of a line that is perpendicular to y=5/2x +3 whose y intercept=8
Answers
Answered by
1
Step-by-step explanation:
3
x
−
5
y
+
12
=
0
Explanation:
The two lines are perpendicular to each other, if the product of their slopes is
−
1
. Hence if slope of one line is given as
a
b
, slope of line perpendicular to it is
−
b
a
.
As equation of one line is given in slope-intercept form as
y
=
−
5
3
x
−
8
, its slope is
−
5
3
.
Hence slope of line perpendicular to it is
3
5
.
Now equation of line passing through
(
x
1
,
y
1
)
and having slope
m
is
(
y
−
y
1
)
=
m
(
x
−
x
1
)
Hence, equation of a line passing through
(
−
9
,
−
3
)
and having a slope
3
5
is
(
y
−
(
−
3
)
)
=
3
5
(
x
−
(
−
9
)
)
or
5
(
y
+
3
)
=
3
(
x
+
9
)
or
5
y
+
15
=
3
x
+
27
or
3
x
−
5
y
+
12
=
0
graph{(3x-5y+12)(y+5x/3+8)((x+9)^2+(y+3)^2-0.05)=0 [-20, 20, -10, 10]} to
Similar questions