Question

write the equation of any LINE which is perpendicular to the line 3x-4y+9=0

Answer 1

Product of the slopes of two lines perpendicular to each other is −1. Let the slope of desired line be m.

Writing the equation of given line 3x+4y=12in slope intercept form, we get

4y=−3x+12 or y=−34x+3

Hence slope of this line is −34.

As such we have −34×m=−1

or m=−1×4−3=43

Hence, slope of desired line is 43 and as it passes through (7,1)

we can have equation of desired line using point slope form of equation i.e.

(y−1)=43(x−7)

or 3((y−1)=4(x−7)

or 3y−3=4x−28

or 4x−3y−25=0

Answer 2

Answer:

Step-by-step explanation:

The line perpendicular to the line 3x-4y+9=0 is 4x+3y+k=0.