Question

Write the equation of line in slope-intercept form Line parallel to y=0.5x+3 that passes through the point (−9,12)

Answer 1

Hey dear here is the answer

Standard Form of Equation of the line:
y=mx+b
Given line
y=5x
Compare above equation with the standard form equation
Slope = m=5 and y-intercept = b=0
Since parallel lines have same slope so slope of the required line will be:-
m=5 

Now we have a point(2,-1) and slope (5)of the line we can easily find required lines by putting these values in the equation of the straight line poin-slope form.
m=(y2-y1)/(x2-x1)
5=(y-(-1))/(x-2)
5=(y+1)/(x-2)
5(x-2)=y+1
5x-10=y+1
y+1=5x-10
y=5x-10-1
y=5x-11
Above equation is the required equation of the line that is parallel to y=5x and contains (2,-1)


3x-x+2=4


Hope it helps you

Answer 2

x
$2 {?}^{2}$