Question

write the equation of line passing through (-1,1) and making an angle 2π/3 with x axis​

Answer 1

Answer:

√3x+y+√3-1=0

Step-by-step explanation:

general equation of line is

y = mx + c

here m=tan2π/3

=tan(π-π/3)

=-tan π/3

=-tan 60

m=-√3

So the equation can be

y=-√3 x+c

The line passes through (-1,1)

Or 1=-√3*(-1)+c

1=√3+c

c=1-√3 So eqn becomes

y=-√3 x+1-√3

Or √3x+y+√3-1=0