Question

write the equation of line passing through (3,-3) and (6,-6)

Answer 1

Step-by-step explanation:

x-x1/(y-y1). =(x2-x1)/(y2-y1)

since the line passing through (-3,3)and(6,-6)

so

(x-3)/(y+3)=(6-3)/(-6+3)

or, (x-3)/(y+3)=-1

or,x+y=o. this is the required equation of the line.