write the equation of parabola whose focus is at (0,-4) and vertex is at (0,0)
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VF=aVF=a
⇒VF=(0−0)2+(2−4)2−−−−−−−−−−−−−−−√=2⇒VF=(0−0)2+(2−4)2=2
Hence a=2a=2
∴∴ The required equation of the parabola is (x−0)2=−4(2)(y−4)(x−0)2=−4(2)(y−4)
⇒x2=−8(y−4)⇒x2=−8(y−4)
Or x2=32−8yx2=32−8y is the required equation of the parabola.
⇒VF=(0−0)2+(2−4)2−−−−−−−−−−−−−−−√=2⇒VF=(0−0)2+(2−4)2=2
Hence a=2a=2
∴∴ The required equation of the parabola is (x−0)2=−4(2)(y−4)(x−0)2=−4(2)(y−4)
⇒x2=−8(y−4)⇒x2=−8(y−4)
Or x2=32−8yx2=32−8y is the required equation of the parabola.
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