Write the equation of state for 16g of O2.
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Answered by
5
No. of moles in 32g of O2 = 1
No. of moles in 16g of O2 = 1/9 x 16 =1/2
As pv = nRT and n=1/2
So, PV=1/2 RT
No. of moles in 16g of O2 = 1/9 x 16 =1/2
As pv = nRT and n=1/2
So, PV=1/2 RT
Answered by
5
Explanation:
we know , PV=NRT
we now that n is the number of moles
NUMBER OF MOLES =GIVEN WEIGHT
--------------------------
MOLECULAR WEIGHT
NUMBER OF MOLES =16/32
=1/2
HENCE , PV=RT/2
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