Math, asked by 22karissarucker, 9 months ago

Write the equation of the circle graphed below.

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Answered by praneethppk123
0

Answer:

The general form of cirle is

x²+y²+2gx+2fy+c=0

Hete(-g,-f) is center

Given (-1,1) is a centre

Radius=

 \sqrt{g { \: }^{2} + f {}^{2}  - c }

From figure we find out radius as square root of 74

1+1-c = 74

C=-72

Eq of circle is x²+y2-2x+2y-72=0

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