Write the equation of the circle passing through (5,4) and (-3,12) and whose centre lies on 14x + y = -38.
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Answer:
Step-by-step explanation:
by algebraic parametric form
center can be taken as
t,-38-14t
now apply distance formula and equate the distance
(t-5)^2+(42+14t)^2 = (t+3)^2+(50+14t)^2
you will be getting linear expression in t
that means only one circle satisfies the conditions
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