Math, asked by trinityjan00, 6 months ago

Write the equation of the circle that has a center of (-7, 17) with a radius of 19.

Answers

Answered by rinyi
4

Answer:

x²+y²+14x-34y-23=0

Step-by-step explanation:

please refer to the attachment

Attachments:
Answered by VaibhavSR
0

Answer:

the equation of the circle is

x² + y² + 14x - 34y -23 = 0

Step-by-step explanation:

General form of Equation of a Circle

The general equation of any type of circle is represented by: x2 + y2 + 2gx + 2fy + c = 0, for all values of g, f and c.

The standard form equation of a circle is given by: (x – x1)² + (y – y1)²= r², where (x, y) is the arbitrary coordinates on the circumference of the circle, r is the radius of the circle, and (x1, y1) are the coordinates of the center of the circle.

Given.

center = ( -7, 17 )

Radius =19

To find

we have to find the equation of the circle

Solution

(x-h)² + ( y-k ) ² = r²

(x-(-7))² + ( y-17) ² = 19²

(x+7))² + ( y-17) ² = 19²

x² +14x +49 +y² -34y +289= 361

x² + y² + 14x - 34y +49 + 289 -361 =0

x² + y² + 14x - 34y -23 = 0

the equation of the circle is

x² + y² + 14x - 34y -23 = 0

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