Question

write the equation of the directris of the parabola x^2-4x-8y+12​

Answer 1

Answer: y+1=0

Step-by-step explanation:

Given parabola x^2-4x-8y+12=0

x^2-4x=8y-12

x^2-2×2× x+(4-4)=8y-12

(x-2)^2=8y-12+4

(x-2)^2=8y-8

(x-2)^2=4.2(y-1)

This is of the form X^2=4ay

Where X=x-2, a=2, and Y=y-1

Now, for equation of directrices

Directrix is Y+a=0

(y-1)+2=0

y+1=0

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