write the equation of the following,
some of two number is 11
diffrence of p and q is 26
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Answer:
1)Given sum of two numbers is 11
x+y=11 _____ (1)
sum of their reciprocals is
28
11 .
x
1
+
y
1
=
48
11
xy
y+x
=
48
11
28(x+y)=11xy _______ (2)
28(11)=11.xy
xy=28
Now
(x−y)
2
=x
2
+y
2
−2xy
(x−y)
2
=(x+y)
2
−4xy
(x−y)
2
=(11)
2
−4×28
(x−y)
2
=121−112
(x−y)
2
=9
x−y=
9
x−y=3 _______ (3)
On adding (1) & (3)
x+y=1
x−y=3_________
2x=14
x=
2
14
x=7
putting x=7 in equation _____ (1)
x+y=11
7+y=11
y=11−7
y=4
∴ The two numbers are (x,y)=7,4
2) please write second question properly please
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