Question

write the equation of the following,
some of two number is 11
diffrence of p and q is 26 ​

Answer 1

Answer:

1)Given sum of two numbers is 11

x+y=11 _____ (1)

sum of their reciprocals is

28

11 .

x

1

+

y

1

=

48

11

xy

y+x

=

48

11

28(x+y)=11xy _______ (2)

28(11)=11.xy

xy=28

Now

(x−y)

2

=x

2

+y

2

−2xy

(x−y)

2

=(x+y)

2

−4xy

(x−y)

2

=(11)

2

−4×28

(x−y)

2

=121−112

(x−y)

2

=9

x−y=

9

x−y=3 _______ (3)

On adding (1) & (3)

x+y=1

x−y=3_________

2x=14

x=

2

14

x=7

putting x=7 in equation _____ (1)

x+y=11

7+y=11

y=11−7

y=4

∴ The two numbers are (x,y)=7,4

2) please write second question properly please