Question

write the equation of the following velocity uniform circular motion
equation for velocity time relation pls urgent​

Answer 1

Answer:

Equation Symbol breakdown

v = r ω v = r \omega v=rω v v v is linear speed, r is radius, ω is angular speed.

T = 2 π ω = 1 f T = \dfrac{2\pi}{\omega} = \dfrac{1}{f} T=ω2π=f1 T T T is period, ω is angular speed, and f is frequency

Answer 2

Answer:

Answer

Let the initial velocity of the object = u

Let the object is moving with uniform acceleration, a.

Let object reaches at point B after time, t and its final velocity becomes, v

Draw a line parallel to x-axis DA from point, D from where object starts moving.

Draw another line BA from point B parallel to y-axis which meets at E at y-axis.

The distance covered by the object moving with uniform acceleration is given by the area of trapezium ABDO

Therefore,

Area of trapezium ABDOE =

2

1

× (sum of parallel sides + distance between parallel sides)

Distance(S)=

2

1

(DO+BE)×OE

S=

2

1

(u+v)×t(i)

we know that,

a=

t

v−u

from above equation we can say,

t=

a

v−u

(ii)

After substituting the value of t from equation(ii) in equation (i)

S=

2a

1

(u+v)(v−u)

2aS=(u+v)(v−u)

2aS=v

2

−u

2

Hence Proved.

solution