Question

write the equation of the line parallel to the x-axis at distance 3 units above x-axis

Answer 1

The equation will be (x,3).
The solutions of the equation will be (0,3), (1,3), (2,3), etc.

Answer 2

Answer:

$y=3$

Step-by-step explanation:

We are given that a line parallel to the x-axis at distance 3 units above x-axis

So, y coordinate of all points lie on this line is 3

So, x can be 0 ,1 ,3 , ...

So, Points will be (0,3),(1,3),(2,3) ,...

We will use two point form to find equation :

$(x_1,y_1)=(1,3)\\(x_2,y_2)=(2,3)$

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-3=\frac{3-3}{2-1}(x-1)$

$y-3=0$

y=3

Hence the equation of the line parallel to the x-axis at distance 3 units above x-axis is $y=3$