Question

write the equation of the line parallel to yaxis and passing through the point (-4,-3)


​

Answer 1

Answer:

Step-by-step explanation:

Generally the line equation is y=mx+c so equation of y-axis is x=0.

Slope of the y-axis =0

So y=mx+c

(i) The point (4,0) is in the line

0=0(4)+c

c=0

y=0(4)+0

y=0

So the equation is y=4

(ii) The point (-2,0) is in the line

0=0(-2)+c

c=0

y=0(-2)+0

y=0

So the equation is y=0

(iii) The point(3,5) is in thGenerally the line equation is y=mx+c so equation of y-axis is x=0.

Slope of the y-axis =0

So y=mx+c

(i) The point (4,0) is in the line

0=0(4)+c

c=0

y=0(4)+0

y=0

So the equation is y=4

(ii) The point (-2,0) is in the line

0=0(-2)+c

c=0

y=0(-2)+0

y=0

So the equation is y=0

(iii) The point(3,5) is in the line

5=0(3)+c

c=5

y=0(3)+5

y=5

So the equation is y=5

(iv) The point (-4,-3) is in the line

-3=0(-4)+c

c=-3

y=0(-4)+(-3)

y=-3

So the equation is y=-3