Question

write the equation of the line pareller to the y -axix of distance 11 unit from it two it left
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Answer 1

Step-by-step explanation:

Since, the line is parallel to plane.

Thus (i−j+4k)⋅(i+5j+k)=0

General point on the line is

(λ+2,−λ−2,4λ+3)

For λ=0, a point on this line is (2,−2,3)and distance from r⋅(i+5j+k)=5 is 

d=∣∣∣∣∣∣∣(1)2+(5)2+(1)22+5(−2)+3−5∣∣∣∣∣∣∣

⇒d=∣∣∣∣∣27−10∣∣∣∣∣

⇒d=3310