Question

Write the equation of the line that is parallel to y-axis and passing through the point (i) (4, 0) (ii) (−2, 0) (iii) (3, 5) (iv) (− 4, −3)

Answer 1

Generally the line equation is y=mx+c so equation of y-axis is x=0.
Slope of the y-axis =0
So y=mx+c
(i) The point (4,0) is in the line
0=0(4)+c
c=0
y=0(4)+0
y=0
So the equation is y=4
(ii) The point (-2,0) is in the line
0=0(-2)+c
c=0
y=0(-2)+0
y=0
So the equation is y=0
(iii) The point(3,5) is in the line
5=0(3)+c
c=5
y=0(3)+5
y=5
So the equation is y=5
(iv) The point (-4,-3) is in the line
-3=0(-4)+c
c=-3
y=0(-4)+(-3)
y=-3
So the equation is y=-3

Answer 2

Step-by-step explanation:

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