Question

Write the equation of the line that satisfies the given conditions. Express the final equation in standard form.
Contains the point
(9, 4)
and is perpendicular to the y axis

Answer 1

Step-by-step explanation:

final equation in standard form.

Contains the point (5, 6)and is perpendicular to the y axis

Parallel to the x-axis --> y is constant

y = 6

Answer 2

$\Large{\underline{\underline{\bf{Answer:-}}}}$

y = 4

Step-by-step explanation:

Contains the point (9,4)

Perpendicular to y-axis i.e., x=0

The slope of y axis is undefined (1/0)

A perpendicular line will have a slope that is

the negative reciprocal of (1/0) so m= -(0/1)= 0

i.e., any line parallel to x-axis

Your perpendicular line has point (9,4), slope m=0

Using point slope form: y-y1 = m(x-x1)

where (x1,y1) = (9,4) & m=0

we get, y-4 = 0(x-9)

so, y-4 = 0

y= 4 is your standard format of ax+by=c

$\Large{\underline{\underline{\bf{Thanks}}}}$