Question

write the equation polynomial sum of whose zeroes is 2 and product is -8​

Answer 1

Answer:

x^2-2x-8

as sum of zeroes(S)=2

product of zeroes(P)= -8

quadratic equation When S and P are given is

x^2-Sx+P

putting values we get

f(x)=x^2-2x-8

hope you got it!!!!

Answer 2

Answer:

x^2 + 2x + (-8)

Step-by-step explanation:

sum = 2/1

= -b/a

product = -8/1

= c/a

a=1 b=-2 c=-8

so the equation is

ax^2 + bc + c= 0

x^2 + 2x + (-8)