Question

*Write the equation x^2 - 9 = 13 in the form ax^2 + bx + c = 0 then write the values of a , b and c .* 1️⃣ a = 1, b = 9 ,c = 13 2️⃣ a = 1,b = 0,c = 13 3️⃣ a = 1, b = 0, c = - 22 4️⃣ a = 1 ,b = 0 ,c = 4​

Answer 1

Answer:

a=1 b=0 c=-22

Step-by-step explanation:

$x^{2} -9=13\\x^{2} -9-13=0\\x^{2} -22=0$

so a=1 b=0 and c=-22

Answer 2

Solution :-

given equation is ,

→ x² - 9 = 13 .

So, in order to write in the form ax^2 + bx + c = 0 , we have to take RHS expression to the LHS in order to make RHS zero .

So,

→ x² - 9 = 13

→ x² - 9 - 13 = 0

→ x² - (9 + 13) = 0

→ x² - 22 = 0

now, writing in the form ax^2 + bx + c = 0 we get,

→ 1•x² + 0•x - 22 = 0

comparing we get,

→ a = 1

→ b = 0

→ c = (-22)

Hence, Option (3) a = 1, b = 0, c = - 22 is correct answer .

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