Question

Write the equivalent Java Expression of the following formulas [2]

x=(-b±√(b^2-4ac))/2a

​

Answer 1

Answer:

Roots of a quadratic equation are determined by the following formula:

x=−b±b2−4ac‾‾‾‾‾‾‾‾√2a

x

=

−

b

±

b

2

−

4

a

c

2

a

To calculate the roots −

Calculate the determinant value (b*b)-(4*a*c).

If determinant is greater than 0 roots are [-b +squareroot(determinant)]/2*a and [-b -squareroot(determinant)]/2*a.

If determinant is equal to 0 root value is (-b+Math.sqrt(d))/(2*a)

Example

import java.util.Scanner;

public class RootsOfQuadraticEquation {

public static void main(String args[]){

double secondRoot = 0, firstRoot = 0;

Scanner sc = new Scanner(System.in);

System.out.println("Enter the value of a ::");

double a = sc.nextDouble();

System.out.println("Enter the value of b ::");

double b = sc.nextDouble();

System.out.println("Enter the value of c ::");

double c = sc.nextDouble();

double determinant = (b*b)-(4*a*c);

double sqrt = Math.sqrt(determinant);

if(determinant>0){

firstRoot = (-b + sqrt)/(2*a);

secondRoot = (-b - sqrt)/(2*a);

System.out.println("Roots are :: "+ firstRoot +" and "+secondRoot);

}else if(determinant == 0){

System.out.println("Root is :: "+(-b + sqrt)/(2*a));

}

}

}

Output

Enter the value of a ::

15

Enter the value of b ::

68

Enter the value of c ::

3

Roots are :: -0.04455555833347

Explanation:

Answer 2

Explanation:

equivalent java expression:

x=(-b+Math.sqrt(b*b-4*a*c))/2*a)