Math, asked by dastutan1441, 5 months ago

Write the expanded form of (2x+3y-z)²

Answers

Answered by Anonymous
2

AnsweR :-

\sf {(2x + 3y - z)}^{2}

\sf {(2x)}^{2} +  {(3y)}^{2} +  {( - z)}^{2} + 2(2x)(3y) + 2(3y)( - z) + 2( - z)(2x)

\sf {4x}^{2} +  {9y}^{2} -  {z}^{2} + 12xy  - 6yz  - 4zx

Procedure :-

→ This Question is from the Algebraic identites. Using the 5th Indentity of Algerbric identites that is (x+y+z)² = x²+y²+z²+2xy+2yz+2zx we have solved this problem.

→ In first we have squared 2x and 3y and kept the z as it is. And then first we multiplied the constants in brackets then we multiplied thier product with the 2 which is outside the bracket.

→ And at the end in the final answer we will put negetive (-) sign because the value -z will affect the Signs which are before it because (+)(-) = -.

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Answered by ravibharathi22
2

Answer:

4x² +9y² + z² +12xy -6yz -4xz

Step-by-step explanation:

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