Math, asked by kashivajjalakiranmai, 6 months ago

write the expanded form of the numbers 4348, 30214, 22222, 75025.
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Answers

Answered by bhandariyogita28
7

Answer:

4348: 4000+300+40+8

30214: 30000+200+10+4

22222:20000+2000+200+20+2

75025:70000+5000+20+5.

Step-by-step explanation:

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Answered by Dhruv4886
0

The expanded form of given numbers are

4348 = 4 × 1000 + 3× 100 + 4×10 + 8 × 1

30214 = 3×10000+ 0×1000 + 2× 100 + 1×10 + 4 × 1

22222 = 2×10000+ 2×1000 + 2× 100 + 2×10 + 2×1

75025 = 7×10000+ 5×1000 + 0× 100 + 2×10 + 5×1  

Given:

4348,  30214, 22222, 75025.

To find:

Write the expanded form of the given numbers

Solution:

Note:

As we know the order of the place value in a number

= ten thousands - thousands - hundreds - tens - ones

If adcd is 4 digit number then the expanded form of abcd

= a × 1000  + d × 100 + c × 10 + d×1

Examples:

2345 = 2 × 1000 + 3×100 + 4×10 + 5×1

14609 = 1×10000 + 4×1000 + 6×100 + 0×10 + 9×1

Expanded forms of given numbers

4348 = 4 × 1000 + 3× 100 + 4×10 + 8 × 1

30214 = 3×10000+ 0×1000 + 2× 100 + 1×10 + 4 × 1

22222 = 2×10000+ 2×1000 + 2× 100 + 2×10 + 2×1

75025 = 7×10000+ 5×1000 + 0× 100 + 2×10 + 5×1  

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