Question

write the exponent form of 3 root 7

Answer 1

Answer to your question is √63

Answer 2

Therefore the exponential form of 3√7 is $63^1^/^2$.

Given:

The number 3√7

To Find:

The exponential form of 3√7.

Solution:

The exponential form of the given number can be easily calculated by the following approach.

The given number 3√7

The general exponential form is aⁿ.

where a = base and n = exponent or power

⇒ 3√7 = $3 * 7 ^1^/^2$  = $9^1^/^2*3^1^/^2$ = $( 9*3)^1^/^2$ = $63^1^/^2$

where Base = 63 and Power or exponent = 1/2

Therefore the exponential form of 3√7 is $63^1^/^2$.

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