write the expression (5 - 2i) - 2(3 + i )is a complex number in a standard form
Answers
Answered by
0
Answer:
= -3/
2-i
= (-3)*(2+i)/
(2-i)*(2+i)
= -3 * 2 + (-3) * i/
2 * 2 + 2 * i + (-i) * 2 + (-i) * i
= -6-3i/
4+2i-2i-i2
= -6-3i/
4+2i-2i+1
= -6 +i(-3)/
4 + 1 +i(2 - 2)
= -6-3i/
5
= -1.2-0.6i
Answered by
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Answer:
The Standard from of (5 - 2i ) - 2(3 + i ) is - ( 1 + 4i )
Explanation:
(5 - 2i ) - 2(3 + i )
= 5 - 2i - 6 - 2i
= - 1 - 4i
= -( 1 + 4i )
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