Question

Write the expression for equilibrium constant Kc for the following equilibrium. CuSO4.5H2O(s) -------------˃ CuSO4.3H2O(s) + 2 H2O(g))​

Answer 1

Explanation:

For the reaction

$CuSO4.5H2O(s)⇌CuSO4.3H2O(s)+2H2O(g)</p><p></p><p></p><p></p><p></p><p>$

The correct representations are

$(A) Kp=(P(H2O))2</p><p>$

$</p><p>(B) Kc=[H2O]2</p><p></p><p></p><p>$

$</p><p>(C) Kp=Kc(RT)2</p><p></p><p>$

$Kp=Kc(RT)Δn </p><p></p><p>$

$and Δn=2</p><p></p><p>$

Note: The concentrations of the solid substances do not appear in the equilibrium constant expression.