Question

Write the expression for equilibrium constant kpfor the reaction 3fe(s)+4h2o(g)→←fe3o4(s)+4h2(g)

Answer 1

hope this will help you

Answer 2

The expression for equilibrium constant $K_p$ for the reaction $3Fe(s)+4H_2O(g)\rightleftharpoons Fe_3O_4(s)+4H_2(g)$  is $K_p=\frac{(p_{H_2})^4}{(p_{H_2O})^4}$ Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{eq}$

$K_p$ is the constant of a certain reaction at equilibrium for gaseous reactants and products.

For the given chemical reaction:

$3Fe(s)+4H_2O(g)\rightleftharpoons Fe_3O_4(s)+4H_2(g)$

The expression of $K_p$ for above equation follows:

$K_p=\frac{(p_{H_2})^4}{(p_{H_2O})^4}$

As solids do not exert pressure, $Fe$ and $Fe_3O_4$ are not involved.

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