Write the expression for Lorentz magnetic field on a particle of charge q moving with velocity v in a magnetic field B. Show that no work is done by this force on the charged particle.
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Answer:Lorentz force = magnetic force + electric force
F = [ qvb sinθ + qe ]
F
=q(
V
×
B
)
(1)
F
is perpendicular to both
V
and
B
.
if
ds
is the instantaneous displacement of the change
ds
is also perpendicular to
F
W=
F
.
ds
= Fs cos90
0
but cos90
0
= 0
W = 0
Hence increase in kinetic energy is zero
Explanation:
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